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[protege-discussion] is-a relationship in SWRL

Timothy Redmond tredmond at stanford.edu
Mon Nov 16 10:16:48 PST 2009


I think that Martin has some SWRL builtins that allow you to do this.

-Timothy


On Nov 11, 2009, at 7:30 AM, Nada Bajnaid wrote:

> then can I inffer about the subclass relationship for ex: subclass (? 
> x,?c) if x is-a subclass of c?
>
> --- On Wed, 11/11/09, Timothy Redmond <tredmond at stanford.edu> wrote:
>
> From: Timothy Redmond <tredmond at stanford.edu>
> Subject: Re: [protege-discussion] is-a relationship
> To: "User support for Core Protege and the Protege-Frames editor" <protege-discussion at lists.stanford.edu 
> >
> Date: Wednesday, November 11, 2009, 9:24 AM
>
>
> On Nov 10, 2009, at 11:00 PM, Nada Bajnaid wrote:
>
> > Thanks Auhood
> >     Then can I have some SWRL rules with is-a and inffer about it?
>
> Yes this is part of the SWRL language.  For instance to say that the  
> SWRL variable ?x is a member of the Pizza class you can write
>
>     Pizza(?x)
>
> -Timothy
>
>
> >
> > Regards
> > Nada
> >
> > --- On Tue, 11/10/09, A A <auhoodf at gmail.com> wrote:
> >
> > From: A A <auhoodf at gmail.com>
> > Subject: Re: [protege-discussion] is-a relationship
> > To: "User support for Core Protege and the Protege-Frames editor" <protege-discussion at lists.stanford.edu 
> >
> > Date: Tuesday, November 10, 2009, 8:48 AM
> >
> >
> >
> > I think the is-a relation is defined as a subclass relation  
> implicitly. so you don't need to define it again.
> > you can see the results when reasoning, e.g. if you write a query  
> that finds all individuals of type persons  you should be able to  
> get all females as well as all individuals defined as persons.
> >
> > Auhood
> >
> >
> > On 10 Nov 2009, at 12:26, Nada Bajnaid wrote:
> >
> > > where could I read more about is-a relationship. if I have  
> female subclass of person then we have female is-a person. Do I need  
> to define object property and name it is-a or its already defined by  
> the subclass relationship? and how I could use it in the reasoning?
> > >
> > > Thanks
> > > Nada
> > >
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